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pedido matriz 25-15-15-12 fixas=??


adhemar

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Com 12 Fixas, restam 3 em 13. A menor distribuição para isolar unicamente 3 que encontrei no momento foi distribuindo as 13 em 3 grupos onde um deles contem 2 Dezenas, desmembre e combine

6A + 5B + 2C = 13 D, enquanto a soma das partes = 3 D, e então terá 12 + 3 = 15 D/jogo

ou seja:

6A   5B   2C    
0   0   0    
1   1   1    
2   2   2    
3   3        
            NJ
0A   1B   2C   5
0A   2B   1C   20
0A   3B   0C   10
1A   0B   2C   6
2A   0B   1C   20
3A   0B   0C   20
1A   2B   0C   60
2A   1B   0C   75
           
             

 

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