Ailton Posted May 17, 2018 Share Posted May 17, 2018 Olá pessoal. Estou sem postar a muito tempo, mas revisitando tópicos antigos de muitos colegas do forum, tive esta ideia: Que tal desdobrarmos as lacunas ocupadas pelas ausentes, mas não dezena por dezena, mas blocos de dezenas. Exemplo: se 567 ficaram ausentes, é uma "lacuna" de trinca; se 15 e 16 ficaram ausentes = lacuna de duque... e assim sucessivamente.... Se 13 e 15 ausentes dua dezenas isoladas, ou seja, blocos de lacunas. Isso daria certo ? Muitos volantes ?? Quote Link to comment Share on other sites More sharing options...
MOC Posted May 18, 2018 Share Posted May 18, 2018 @Ailton, pode ser uma boa. Dando uma olhada nas lacunas, percebi um certo padrão nas lacunas verticais(atrasos): Normalmente não temos 2 dezenas atrasadas mais que 4 concursos ao mesmo tempo. às vezes aparece 5 atrasos, ou 6, mas o normal é uma delas sair com já no quinto sorteio. Pode acrescentar algo à mais na sua ideia... Vamos trabalhando 1 3 5 7 10 12 13 15 17 19 20 21 23 24 25 1 2 6 7 8 9 10 11 12 14 17 18 19 24 25 1 2 3 5 6 7 9 10 15 16 17 18 20 21 25 1 3 4 8 10 11 12 13 15 16 17 22 23 24 25 4 9 10 11 12 13 16 18 19 20 21 22 23 24 25 1 4 7 8 9 10 11 13 17 20 21 22 23 24 25 2 4 5 6 7 9 10 11 13 17 18 21 23 24 25 1 2 3 6 9 10 11 13 15 17 18 19 23 24 25 1 2 3 4 5 6 9 12 15 17 18 21 22 24 25 2 4 5 6 8 9 10 12 13 14 16 17 18 19 24 1 3 4 6 9 11 12 13 15 16 17 18 21 22 25 1 2 4 8 10 11 12 13 14 15 17 18 20 23 25 1 3 4 5 10 11 13 15 16 17 19 21 23 24 25 1 3 4 7 9 11 13 15 18 19 20 21 23 24 25 3 4 5 8 10 11 13 15 17 20 21 22 23 24 25 1 2 4 7 8 10 13 15 16 18 19 20 21 22 25 2 6 8 9 10 11 12 13 14 16 19 20 23 24 25 1 2 6 7 8 9 10 11 13 14 15 19 20 22 23 1 Quote Link to comment Share on other sites More sharing options...
Julio Cezar Posted February 7, 2019 Share Posted February 7, 2019 Gosto de observar a oportunidade de retorno observando o ocorrido a partir de 3 colunas de 6Dz quando os extremos somados favorece a balança, fazendo pender um lado com mais ausentes procurando 6 com mais de 3 ausentes. caso possa nos ajudar com sua opinião, verifique o entendimento e comente. Observe distancias Quote Link to comment Share on other sites More sharing options...
Julio Cezar Posted August 4, 2020 Share Posted August 4, 2020 Caso 14 ou 15 em 18 2 2 2 2 5 5 5 5 5 Tome 7 D com 5 + 2 para isolar 5 frias de 5 X 1 e de 2 X 1 e assim terá 2 fixas em 25 - 7 = 18 Dz e 18 terá 13 com 2 = 15 Acertos. É só tudo isto, e matriciar 18 D Pesquisar para escolher os grupos de 2 e de 5 a aplicar Sorteio 2001 - teve estes 04 12 15 18 22 e 11 24 = 5 frias , logo 2 fixas 22 e 11 Spoiler 5 18 6 19 7 20 11 24 1 2 6 11 20 3 17 23 24 25 4 12 15 18 22 5 8 16 19 21 7 8 9 13 14 0 1 1 0 1 0 1 1 1 1 1 1 0 1 1 1 1 1 1 0 0 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 1 1 1 1 0 1 0 0 1 0 1 1 1 0 0 1 1 0 0 0 1 0 1 1 0 1 0 1 1 0 1 0 1 1 1 1 1 1 0 0 1 0 1 1 0 0 1 1 0 1 1 1 1 1 0 0 0 1 0 0 1 1 1 0 1 1 0 0 1 1 1 0 1 1 1 1 0 0 0 0 1 1 0 1 0 1 0 0 1 0 0 0 0 1 0 0 0 1 0 1 0 1 1 1 1 1 1 0 0 1 0 0 1 0 1 1 1 1 0 0 1 0 0 1 1 1 1 0 1 0 0 0 0 1 1 1 1 1 0 1 1 1 0 1 1 0 1 0 1 1 1 1 1 0 1 1 0 1 0 1 1 0 1 0 0 1 1 0 0 0 0 1 1 1 1 1 0 1 1 1 1 0 1 1 0 1 1 1 1 1 1 0 1 1 1 1 0 0 0 1 1 0 1 0 0 0 1 1 1 1 0 1 1 1 0 1 1 1 0 1 0 1 0 0 0 1 0 0 1 0 1 0 0 1 1 1 1 1 0 1 1 0 1 1 0 1 0 1 1 0 0 0 1 0 1 1 0 0 1 0 1 1 0 1 0 0 1 1 1 1 0 1 0 1 1 1 1 0 1 0 1 0 1 1 1 1 1 1 1 1 0 0 1 1 1 0 0 1 1 1 1 0 1 1 0 1 1 0 1 0 1 1 0 1 0 0 0 0 1 0 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