angel Posted June 29, 2014 Share Posted June 29, 2014 pode ser 100% Quote Link to comment Share on other sites More sharing options...
ivanor Posted June 29, 2014 Share Posted June 29, 2014 Espero que sirva 100%01 02 03 06 08 09 12 13 15 1801 02 03 04 05 11 12 14 15 2001 02 03 04 09 10 11 13 17 2001 02 04 05 07 08 11 13 17 1901 02 05 07 08 09 15 16 19 2001 02 05 09 12 13 14 16 19 2001 02 06 07 10 12 13 15 17 1801 02 07 08 09 10 11 12 15 2001 03 04 06 07 12 14 15 18 1901 03 04 07 10 11 12 16 17 1801 03 04 06 08 09 14 17 18 2001 03 05 06 08 10 15 17 18 1901 03 08 09 10 11 15 16 17 1901 03 10 12 13 15 16 18 19 2001 04 05 06 07 09 10 13 19 2001 04 07 08 09 11 14 15 16 1801 05 08 11 13 14 16 17 18 2001 06 08 09 12 13 17 18 19 2002 03 04 05 07 08 09 12 15 1902 03 06 07 08 11 14 16 19 2002 04 05 09 11 12 13 17 18 2002 04 05 06 09 10 13 14 15 1902 04 05 06 07 08 11 15 17 1802 04 05 11 12 14 15 16 17 1902 04 06 07 09 10 11 15 18 2002 04 09 14 15 16 17 18 19 2002 05 06 08 09 12 14 18 19 2002 05 06 08 09 10 11 13 14 1703 04 05 06 08 11 12 14 17 1803 04 06 07 08 10 11 13 15 1603 04 06 10 11 13 14 16 18 2003 04 07 08 09 10 12 13 14 2003 05 06 08 09 12 13 16 18 1903 05 08 09 10 12 14 16 17 2003 06 07 09 10 13 14 16 17 1803 07 08 09 11 12 13 14 17 1904 05 07 10 13 14 15 17 18 2005 07 08 10 11 12 15 16 18 20 IVANOR Quote Link to comment Share on other sites More sharing options...
Mauricio Samy Posted June 29, 2014 Share Posted June 29, 2014 C(20,10,3) <=15 Method of construction: lex covering 01 02 03 04 05 06 07 08 09 10 01 02 03 04 05 06 07 08 19 20 01 02 11 12 13 14 15 16 17 18 01 03 04 05 06 15 16 17 18 19 01 03 04 09 10 11 12 17 18 20 01 03 04 09 10 13 14 15 16 19 01 05 06 07 08 11 12 17 18 19 01 05 06 07 08 13 14 15 16 20 01 07 08 09 10 11 12 13 14 19 02 03 04 07 08 11 12 15 16 20 02 03 04 07 08 13 14 17 18 19 02 05 06 09 10 11 12 15 16 19 02 05 06 09 10 13 14 17 18 20 03 04 05 06 11 12 13 14 19 20 07 08 09 10 15 16 17 18 19 20 1 Quote Link to comment Share on other sites More sharing options...
angel Posted June 29, 2014 Author Share Posted June 29, 2014 aos colegas que mandaram bem.para cada matriz pode vir varios com 3 pontos.por exemplo em cada linha pode vir teoricamente varios 3 pontos? Quote Link to comment Share on other sites More sharing options...
Mauricio Samy Posted June 30, 2014 Share Posted June 30, 2014 A condição é que, havendo 3 dezenas entre as sorteadas, haverá 3 acertos na matriz e se ocorrer mais de 3 dezenas sorteadas a premiação será: acertando ...3 = 3 pontos4 = min 4 com 3 pontos5 = min 10 com 3 pontos6 = min 3 com 4 e 8 com 3 pontos7 = min 7 com 4 e 7 com 3 pontos Quote Link to comment Share on other sites More sharing options...
Igor Enrick Posted July 7, 2020 Share Posted July 7, 2020 Em 29/06/2014 em 16:44, Mauricio Samy disse: C(20,10,3) <=15 Method of construction: lex covering 01 02 03 04 05 06 07 08 09 10 01 02 03 04 05 06 07 08 19 20 01 02 11 12 13 14 15 16 17 18 01 03 04 05 06 15 16 17 18 19 01 03 04 09 10 11 12 17 18 20 01 03 04 09 10 13 14 15 16 19 01 05 06 07 08 11 12 17 18 19 01 05 06 07 08 13 14 15 16 20 01 07 08 09 10 11 12 13 14 19 02 03 04 07 08 11 12 15 16 20 02 03 04 07 08 13 14 17 18 19 02 05 06 09 10 11 12 15 16 19 02 05 06 09 10 13 14 17 18 20 03 04 05 06 11 12 13 14 19 20 07 08 09 10 15 16 17 18 19 20 É 100% essa matriz amigo? Quote Link to comment Share on other sites More sharing options...
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